Solution - Factoring binomials using the difference of squares

Step  1  :

Trying to factor as a Sum of Cubes :

 1.1      Factoring:  m³+216 

Theory : A sum of two perfect cubes,  a³ + b³ can be factored into  :
             (a+b) • (a²-ab+b²)
Proof  : (a+b) • (a²-ab+b²) =
    a³-a²b+ab²+ba²-b²a+b³ =
    a³+(a²b-ba²)+(ab²-b²a)+b³=
    a³+0+0+b³=
    a³+b³

Check :  216  is the cube of   6 
Check :  m³ is the cube of   m¹

Factorization is :
             (m + 6)  •  (m² - 6m + 36) 

Trying to factor by splitting the middle term

 1.2     Factoring  m² - 6m + 36 

The first term is,  m²  its coefficient is  1 .
The middle term is,  -6m  its coefficient is  -6 .
The last term, "the constant", is  +36 

Step-1 : Multiply the coefficient of the first term by the constant   1 • 36 = 36 

Step-2 : Find two factors of  36  whose sum equals the coefficient of the middle term, which is   -6 .

For tidiness, printing of 12 lines which failed to find two such factors, was suppressed

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Final result :

  (m + 6) • (m2 - 6m + 36)